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Question : 76 of 160
Marks:
+1,
-0
Solution:
Consider the given integral,
x= xdt= Take
e−=u then,
e−dt=−2du Att=loge2,u= At t=x,u=e− Substitute these values in the above expression.
e= sin−1(e−)−=− sin−1(e−)= e−= −=loge() =−loge(2) x=2loge(2)
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