AP EAMCET Engineering 20 Apr 2019 Shift 1 Paper

The equation of line through the intersection of given lines is
(3x−4y+1)+λ(5x+y−1)‌‌=0
   (3+5λ)x+(λ−4)y‌‌=(λ−1)
      ‌

x

λ−1 3+5λ

+‌

y

λ−1 λ+4

=1
From the given information,
‌

λ−1

3+5λ

=‌

λ−1

λ−4

‌ and ‌λ≠1
Then
λ−4‌‌=5λ+3
 4λ‌‌=−7
 λ‌‌=−‌

7

4

So, equation of the required line is,
(3−‌

35

4

)x+(−‌

7

4

−4)y‌‌=(−‌

7

4

−1)
      −‌

23

4

x−‌

23

4

y‌‌=−‌

11

4

       23x+23y‌‌=11