AP EAMCET Engineering 20 Apr 2019 Shift 1 Paper

The mean of given data is,
x‌‌=‌

a0+a1+a2+...+a11

12

‌‌=‌

a0+a11

2

‌‌=‌

a1+a10

2

‌‌=...
Then the deviation from mean is given by,
|x−a0|‌‌=‌

|a11−a0|

2

‌‌=‌

11|d|

2

And,
|x−a1|‌‌=‌

|a10−a1|

2

‌‌=‌

9|d|

2

,...
So, sum of deviations is,
2[‌

11|d|

2

6+‌

9|d|

2

+‌

7|d|

2

+‌

5|d|

2

+‌

3|d|

2

+‌

|d|

2

]=36|d|
The mean deviation from arithmetic mean is given by,
‌

36|d|

12

=3|d|