AP EAMCET Engineering 20 Apr 2019 Shift 1 Paper

Section: Mathematics
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Question : 3 of 160
 
Marks: +1, -0
Assertion (A) : (1) + (1+2+4) + (4+6+9) + (9+12+16) + ... + (81+90+100) = 1000
Reason (R) :
n
Σ
r=1
(r3−(r−1)3)
= n3 for any natural number n
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