AP EAMCET Engineering 20 Apr 2019 Shift 1 Paper

Section: Mathematics

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Question : 18 of 160

Marks: +1, -0

Jf

(1−px)−1

(1−qx)

= a0+a1x+a2x2+a3x3 + ... , then an =

pn+1−qn+1
q−p
pn+1−qn+1
p−q
pn−qn
q−p
pn−qn
p−q

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