AP EAMCET Engineering 20 Apr 2019 Shift 1 Paper

The condition for interference maxima is given as,
d‌sin‌θ=nλ‌quad...(I)
Substituting the given values in above expression, we get
2λ‌sin‌θ=nλ
2‌sin‌θ=n
The maximum value of sin‌θ comes out to be 1
The value of n comes out to be: n=2×1=2
Thus, total 5 integer is possible for equation
(I) which are
−2,−1,0,1,2