AP EAMCET Engineering 18 Sep 2020 Shift 2 Paper

A=(3,1)
Let slope of line be m
∴‌‌y−y1=m(x−x1)‌‌ [be the required line]
y−1=m(x−3)
y−1=mx−3m
mx−y+(1−3m)=0....(i)The greatest distance of line from origin passes through A(3,1) is perpendicular to the given line.
∴‌‌OA⟂PQ
Slope of OA× Slope of PQ=−1
‌

1

3

×m=−1⇒m=−3
Put, m=−3 in Eq. (i)
−3x−y+(1−3)(−3)=0
−3x−y+(10)=0
3x+y+10=0
∴ Area of