AP EAMCET Engineering 18 Sep 2020 Shift 2 Paper

Section: Mathematics

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Question : 47 of 160

Marks: +1, -0

The equation of the transverse axis of hyperbola (x−3)2+(y+1)2=(4x+3y)2 is

3x+4y=13
3x−4y=13
4x−3y=13
3x−4y=9

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