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Question : 70 of 160
Marks:
+1,
-0
Solution:
I=∫‌| cos‌7‌x−cos‌8‌x |
| 1+2‌cos‌5‌x |
dx =∫‌| cos‌7‌x−cos‌8‌x |
| 1+2−4sin2(‌) |
dx =∫‌| 2‌sin‌‌sin‌ |
| 3−4sin2(‌) |
dx =∫‌| 2‌sin‌‌sin‌‌sin‌ |
| 3‌sin‌−4sin3‌ |
dx =‌‌sin‌2‌x−‌‌sin‌3‌x+c
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