Equation of the line passing through the intersection of the plane x + 2y + 3z = 4 and the line {x-1}/2={y+1}/1=\frac{z-1}{-1} and parallel to the vector (2 i^{ ∧} - 3 j ^{ ∧}) \times ( i^{ ∧} + 2j^{ ∧} - k^{ ∧}) is

Correct Answer is : x−5−3=y−1−2=z+1−7

\frac{x-5}{-3}=\frac{y-1}{-2}=\frac{z-1}{7}

\frac{x-5}{-3}=\frac{y-1}{-2}=\frac{z+1}{-7}

\frac{x-5}{-3}=\frac{y-1}{2}=\frac{z+1}{7}

AP EAMCET Engineering 18 Sep 2020 Shift 1 Paper

Section: Mathematics

Question : 64 of 160

Marks: +1, -0

Equation of the line passing through the intersection of the plane x+2y+3z=4 and the line

x−1

y+1

z−1

−1

and parallel to the vector (2

∧

−3

∧

)×(

∧

−

∧

) is

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