AP EAMCET Engineering 18 Sep 2020 Shift 1 Paper

Section: Mathematics
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Question : 49 of 160
 
Marks: +1, -0
The radical centre of the circles x2+y2−4x−6y+5=0, x2+y2−2x−4y−1=0 and x2+y2−6x−2y=0 is equal to
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