\int\sqrt{x-1}(x\sqrt{x+1})^{-1} dx=

Correct Answer is : ln|x+√x2−1|−Sec−1(x)+c

\ln|x+\sqrt{x^2-1}|-\Sec^{-1}(x)+c

\ln|x-\sqrt{x^2-1}|-\Tan^{-1}(x)+c

\ln|x+\sqrt{x^2-1}|+\Sec^{-1}(x)+c

\ln|x+\sqrt{x^2-1}|-\Tan^{-1}(x)+c

AP EAMCET Engineering 18 Sep 2020 Shift 1 Paper

Section: Mathematics

Question : 31 of 160

Marks: +1, -0

∫√x−1(x√x+1)−1dx=

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