AP EAMCET Engineering 18 Sep 2020 Shift 1 Paper

Hybridisation state of Be in BeF2 is sp.
F→Be−F
H=‌

1

2

(V+M−C+A)
=‌

1

2

(2+2−0+0)=2(sp)
where,
V= number of valence electrons of Be=2
H= number of monovalent F atom =2
C= number of cationic charge =0
A= number of anionic charge =0
So, the hybridisation of Be in BeF2 molecule is sp.