AP EAMCET Engineering 17 Sep 2020 Shift 2 Paper

Section: Mathematics

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Question : 69 of 160

Marks: +1, -0

The polar of (1,−2) with respect to x2+y2−10x−10y+25=0 is

4x+7y+30=0
4x+7y−30=0
4x−7y+30=0
x+y=0

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