AP EAMCET Engineering 17 Sep 2020 Shift 2 Paper

Box contains 4 defective and 6 good machines.
∴ Total number of machines =10
Probability that first machine selected is good
=‌

‌ Number of good ‌m/c

‌ Total number of ‌m/c

=‌

6

10

Probability that second machine is good =‌

5

9

Probability that both machines are good
=‌

6

10

×‌

5

9

=‌

1

3