AP EAMCET Engineering 17 Sep 2020 Shift 2 Paper

Let image is P′(h,k)Then PP′ is perpendicular to given line and mid point of PP′ lies over line.
So, we have
(‌

8−k

3−h

)×‌

−1

3

=−1 .....(i)
And,

3+h

2

+3(‌

8+k

2

)=7
3+h+24+3k=14
⇒‌‌h+3k+13=0....(ii)
From Eqs. (i) and (ii), we have
h=−1 and k=−4
So image is, (−1,−4).