AP EAMCET Engineering 17 Sep 2020 Shift 2 Paper

Section: Mathematics

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Question : 16 of 160

Marks: +1, -0

The equation of tangent to the curve y=5x2−3x+7 at the point (−1,4) is _______

13x−y−9
13x+y−9
13x+y+9
13x+2y+5

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