AP EAMCET Engineering 17 Sep 2020 Shift 2 Paper

The given situation is shown in the following figure.If time taken by the ball to reach at highest point A is t, then
0=v−gt⇒t=‌

V

g

Total time taken to reach the ball from point of projection to reach at point B is given as
t1=t+t=2t⇒t1=‌

2v

g

If t2 be the time taken by the ball to reach from point B to point C, then
∴‌‌t2=‌

−2v±√4v2+8gh

2g

t2=‌

−v

g

+√‌

v2+2gh

2

[taking +ve sign because time is positive]
∴ Total time,