AP EAMCET Engineering 17 Sep 2020 Shift 2 Paper

Given, frequency of tuning fork X and Y are,
nX=280Hz
nY=284Hz
nZ=?
When tuning forks X and Z are sounded together, then beats produced is b (assume).
∴‌‌nZ−nX=b..........(i)
Again, when Y and Z are sounded together, then
nz−nY=3b...(ii)
Dividing Eq. (i) by Eq. (ii), we have
‌

nZ−nX

nZ−nY

=‌

b

3b

⇒‌

nZ−280

nZ−284

=‌

1

3

⇒‌‌3nz−840=nz−284
⇒‌‌3nz−nZ=840−284
⇒‌‌2nZ=556⇒nZ=278Hz