AP EAMCET Engineering 17 Sep 2020 Shift 1 Paper

Given hyperbola ‌

x2

9

−‌

y2

1

=1
So, y=mx±√9m2−1 represent tangents which passes through (3,2)
⇒‌‌m=‌

5

12

∴ Tangents are
12y=5x+9 and x=3
Chord of contact will be ‌

xx1

a2

−‌

yy1

b2

=1
⇒‌‌‌

3x

9

−‌

2y

1

=1⇒x−6y=3
The vertices of the triangle formed with tangents and chord will be (3,2),(3,0) and
(−5,−‌

4

3

)
So, area of