If y= \sin^{98}(x).\cos^39(x), find \frac{dy}{dx}

Correct Answer is : (98cos99x.sin38x)−(39sin40x.cos97x)

(98\cos^99x.\sin^38x)+(39\sin^40x.\cos^97x)

(98\cos^98x.\sin^39x)-(40\sin^39x.\cos^98x)

(98\cos^99x.\sin^38x)-(39\sin^40x.\cos^97x)

(98\cos^98x.\sin^39x)+(39\sin^40x.\cos^97x)

AP EAMCET Engineering 17 Sep 2020 Shift 1 Paper

Section: Mathematics

Question : 58 of 160

Marks: +1, -0

If y=sin98(x).cos39(x), find

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