AP EAMCET Engineering 17 Sep 2020 Shift 1 Paper

Section: Mathematics

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Question : 21 of 160

Marks: +1, -0

The equation of a circle with centre (5,4) and touch the y-axis is

x2+y2−10x−8y−16=0
x2+y2−10x−8y−61=0
x2+y2+10x+8y+16=0
x2+y2−10x−8y+16=0

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