AP EAMCET Engineering 17 Sep 2020 Shift 1 Paper

Centripetal force is given as F=‌

mv2

r

where, m= mass, v= velocity and r= radius.
‌

F2

F1

=‌

m2

m1

⋅(‌

v2

v1

)2⋅(‌

r1

r2

).....(i)
When, mass, speed and radius of circular path of particle increases by 100%, i.e. these become double.
Hence, m2=2m1
v2=2v1
r2=2r1
∴ From Eq. (i), we have
⇒‌‌F2=4F1
Percentage increase in centripetal force,