{\CH}_3- {\CH} ( {\Br}_2) \stackrel{\text{ Alc. }\xrightarrow {\KOH}} {\X} \stackrel{\text{Liq. }{{ \xrightarrow {\NH}}_{{ {\NaNH}_2}}_3}} {\Y} In the above reaction the products {\X} and {\Y} may be

Correct Answer is : CH2=CH−Br,HC≡CH

{\CH}_2= {\CH}- {\Br}, {\HC} \equiv {\CH}

{\HC} \equiv {\CH} , {\CH}_2= {\CH}- {\NH}_2

{\CH}_2= {\CH}- {\Br} , {\CH}_2= {\CH}- {\NH}_2

{\CH}_2= {\CH}_2 , {\HC} \equiv {\CH}

AP EAMCET 22 May 2023 Shift 2 Paper

Question : 138 of 160

Marks: +1, -0

CH3−CH(Br2)‌

‌ Alc. ‌KOH

───────▶

‌X‌

‌Liq. ‌NH

───────▶

NaNH2

3Y
In the above reaction the products X and Y may be

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