A thin oil layer floats on water. A ray of light making an angle of incidence of 45^{\circ} shines on oil layer. The angle of refraction of light ray in water is (\mu_{\text{oil }}=1.54, \mu_{\text{water }}=1.33)

Correct Answer is : Sin−1(√932)

{\Sin}^{-1} (\sqrt{\frac{3}{32}})

{\Sin}^{-1} (\sqrt{\frac{9}{32}})

AP EAMCET 22 May 2023 Shift 2 Paper

Question : 102 of 160

Marks: +1, -0

A thin oil layer floats on water. A ray of light making an angle of incidence of 45∘ shines on oil layer. The angle of refraction of light ray in water is
(µ‌oil ‌=1.54,µ‌water ‌=1.33)

Sin−1(√‌
3
32
)
sin‌−1(‌
3
32
)
sin‌−1(‌
9
32
)
Sin−1(√‌
9
32
)

Validate

Go to Question:

Prev Question

Next Question