The electric field of an electromagnetic wave propagating in vacuum is given by {\E}=35 \cos ( {\kx}-4.5 \times 10^8 {\t}) where {\E}, {\x} and {\t} are in {\Vm}^{-1}, {\m} and s respectively. The magnitude of the propagation vector is

AP EAMCET 22 May 2023 Shift 1 Paper

Question : 114 of 160

Marks: +1, -0

The electric field of an electromagnetic wave propagating in vacuum is given by E=35‌cos(kx−4.5×108t) where E,x and t are in Vm−1,m and s respectively. The magnitude of the propagation vector is

0.5m−1
1m−1
1.5m−1
2m−1

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