The emf of the cell in which the following reaction takes place is {Ni}_{(s)}+2 {{Ag}^{+}}(0.002 {M})\to {Ni}^{2+}(0.160 {M})+2 {Ag}_{( {s})}(E^\circ_{\cell} =1.05V)

AP and TS EAMCET Medical Model Paper 7

Question : 151 of 158

Marks: +1, -0

The emf of the cell in which the following reaction takes place is

Ni(s)+2Ag+(0.002M)→Ni2+(0.160M)+2Ag(s)

(E°cell=1.05V)

Go to Question:

Prev Question

Next Question