\int { 4 \sec ^ { 2 } x \tan x }/ { \sec ^ { 2 } x + \tan ^ { 2 } x } d x =

Correct Answer is : log(sec2x+tan2x)+c

2 \log \left( \sec ^ { 2 } x + \tan ^ { 2 } x \right) + c

\log ( 2 x + \tan ^ { 2 } x ) + c