If y = x ^ { x ^ {x ...\infty } } then { d y } /{ d x } =

Correct Answer is : y2x(1−ylogx)

{ { y } ^ { 2 } }/ { { x } ( 1 + { y } \log { x } ) }

{ { y } ^ { 2 } }/ { { x } ( 1 - \log { x } ) }

{ { y } ^ { 2 } }/ { { x } ( 1 - { y } \log { x } ) }

{ { y } ^ { 2 } }/ { { x } ( 1 + x\log { x } ) }

AP and TS EAMCET Engineering Model Paper 8

Question : 53 of 160

Marks: +1, -0

If y=xxx...∞ then

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