{ \tan \\alpha + \sec \\alpha- 1 }/ { \tan \\alpha - \sec \\alpha + 1 } =

Correct Answer is : 1+sinαcosα

{ 1 - \sin \\alpha} /{ \cos \\alpha }

{ 1 + \sin \\alpha} /{ \cos \\alpha }

{ 1 - \cos \\alpha} /{ \cos \\alpha }

{ 1 + \cos \\alpha} /{ \cos \\alpha }

AP and TS EAMCET Engineering Model Paper 8

Question : 15 of 160

Marks: +1, -0

tan‌α+sec‌α−1

tan‌α−sec‌α+1

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