AP and TS EAMCET Engineering Model Paper 7

© examsiri.com

Question : 51 of 160

Marks: +1, -0

For the circle x2+y2=25, the points (−3,4),(3,−4) are

Inverse points
Conjugate points
Extremities of diameter
Poles of x+y+15=0,x+y−2=0 with respect to x2+y2=25

Go to Question:

Prev Question

Next Question