A unit vector perpendicular to the plane of \ov { {a}}=2 \overline{ {i}}-6 \ov { {j}}-3 \ov { {k}}, \ov { {b}}=4 \ov { {i}}+3 \ov { {j}}-\ov { {k}} is

Correct Answer is : 3i−2j+6k7

{ 4 \ov { { i } } + 3 \ov { { j } } - \ov { { k } } }/ { \sqrt{ 26 } }

{ 2 \ov { { i } } - 6 \ov { { j } } - 3 \ov { { k } } }/ { 7 }

{ 3 \ov { { i } } - 2 \ov { { j } } + 6 \ov { { k } } } /{ 7 }

{ 2 \ov { { i } } - 3 \ov { { j } } - 6 \ov { { k } } }/ { 7 }

AP and TS EAMCET Engineering Model Paper 6

Question : 7 of 160

Marks: +1, -0

A unit vector perpendicular to the plane of a=2i−6j−3k, b=4i+3j−k is

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