\inte ^ { x } ( { 1 + \sin x } /{ 1 + \cos x } ) d x =

Correct Answer is : extan(x2)+c

{ e ^ { x } } /{ 2 } \sec ^ { 2 } ( { x } /{ 2 } ) + c

e ^ { x } \log ( 1 + \cos x ) + c

{ e ^ { x } }/ { ( 1 + \cos x ) ^ { 2 } } + c

e ^ { x } \tan ( { x }/ { 2 } ) + c

AP and TS EAMCET Engineering Model Paper 5

Question : 79 of 160

Marks: +1, -0

∫ex(

1+sin‌x

1+cos‌x

)dx=

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