\int{\sin x}/{\sin ^{2} x+4 \cos ^{2} x} d x=

Correct Answer is : 1√3Tan−1(1√3cosx)+c

{1}/\sqrt{3} {Tan}^{-1} ( {1}/{ {3} \sin x} )+c

{1}/\sqrt{3} {Tan}^{-1} ( {1}/{ {\sqrt3} \cos x} )+c

{1}/\sqrt{3} {Tan}^{-1} ( {1}/{ {\sqrt3} \sec x} )+c

{1}/\sqrt{3} {Tan}^{-1} ( {1}/{ {\sqrt3} \Tan x} )+c

AP and TS EAMCET Engineering Model Paper 3

Question : 71 of 160

Marks: +1, -0

∫

sin‌x

sin2x+4cos2x

dx=

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