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Question : 77 of 160
Marks:
+1,
-0
Solution:
(r+sin‌θ)2‌cos‌θ‌dθ Let
sin‌θ=t⇒cos‌θ‌d‌θ=dt When
θ=0⇒sin‌0=0⇒t=0 θ=⇒sin‌=1⇒t=1 (r+t)2‌dt =(1+t)2dt+(2+t)2dt+.... +(n+t)2dt =[ ]01+[]01+.... .+[ ]01 =−+−+...... +−+− =−= =
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