AP and TS EAMCET Engineering Model Paper 20

The inverse point of (-2, 3) w.r.t. the circle x2+y2−4x−6y+9=0 is the point of intersection of polar and the line joining centre (2, 3) and (-2, 3).
Polar of (-2, 3) w.r.t. the circle x2+y2−4x−6y+9=0 is
−2x+3y−2(x−2)−3(y+3)+9=0
−2x+3y−2x+4−3y−9+9=0
−4x+4=0
x=

−4

−4

=1
Equation of the line y−3=

3−3

−2−2

(x−2)⇒y=3
∴ (1,3)