Let \overline{a}=\overline{i}+\overline{j}+ \overline{k}, \overline{b}=2 \overline{i}-\ov {j}+3 \overline{k}, \overline{c}=\overline{i}-\overline{j} and \overline{d}=6 \overline{i}+2 \ov {j}+3\ov {k} If \overline{{d}}= {x}(\overline{{b}}\times \overline{{c}})+ {y}(\overline{{c}} \times\overline{{a}})+ {z}(\overline{{a}} \times \overline{{b}}) then (x, y, z) =

Correct Answer is : (115,195,45)

( \frac{4}{5}, \frac{11}{5}, \frac{19}{5} )

( \frac{11}{5}, \frac{4}{5}, \frac{19}{5} )

( \frac{11}{5}, \frac{19}{5}, \frac{4}{5} )

( \frac{19}{5}, \frac{11}{5}, \frac{4}{5} )

AP and TS EAMCET Engineering Model Paper 20

Question : 33 of 160

Marks: +1, -0

Let a=i+j+k,b=2i−j+3k, c=i−j and d=6i+2j+3k
If d=x(b×c)+y(c×a)+z(a×b) then (x, y, z) =

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