It is given that (\sin ^{-1} x ) \cos ^{-1} (- \sqrt{3}/{2} )= {5 \\pi^{2}}/{36} . Which one of the following is not correct?

Correct Answer is : (sin−1x)2=19[cos−1(12)]2

(\sin ^{-1} x )^{2}= \frac{1}{9} [\cos ^{-1} ( \frac{1}{2} ) ]^{2}

\sin ^{-1} x= \frac{1}{5} \cos ^{-1} (- {\\sqrt{3}/{2} )

\sin ^{-1} x+\cos ^{-1} ( \sqrt{3}/{2 })= \frac{\\pi}{3}

\sin ^{-1} x-\cos ^{-1} ( \frac{1}{2} ) \neq0

AP and TS EAMCET Engineering Model Paper 20

Question : 23 of 160

Marks: +1, -0

It is given that (sin−1x)cos−1(−

√3

5π2

. Which one of the following is not correct?

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