AP and TS EAMCET Engineering Model Paper 19

diameters of circles lying on lines are x + y – 5 = 0 ------ (1)
2x + y – 7 = 0 ------(2)
point of intersection of (1) and (2) is centre c = (2, 3) given point p = (6, 6)
r=cp=√(6−2)2+(6−3)2 =√25=5