AP and TS EAMCET Engineering Model Paper 18

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Question : 8 of 160

Marks: +1, -0

lim

x→0

8

x8

[1−cos‌

x2

2

−cos‌

x2

4

+cos‌

x2

2

+cos‌

x2

2

‌cos‌

x2

4

] is equal to

1
16
−
1
16
1
32
−
1
32

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