AP and TS EAMCET Engineering Model Paper 18

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Question : 140 of 160

Marks: +1, -0

C2H5COOH

LiAIH4

––––––🢖

(X)

PCC(or)PDC

–––––––––🢖

(Y); Here Y is

CH3CH2CH2OH
CH3COOC2H5
CH3CH2CHO
CH3CH=CH2

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