Given mass number of gold -197 density of gold -19.7 \g \cm ^{3}, Avogadro's number =6\times 10^{23} The radius of the gold atom is approximately.

Correct Answer is : 1.5×10−10m

AP and TS EAMCET Engineering Model Paper 18

Question : 116 of 160

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Given mass number of gold -197 density of gold −19.7g‌cm3, Avogadro's number =6×1023 The radius of the gold atom is approximately.

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