If C is the centre, r is radius of the circle S \equivx^2+y^2+2gx +2fy+c=0 and \A(x_1, y_1), \B(x_2, y_2) are conjugate points with respect to S = 0 then \AB^2 =

Correct Answer is : CA2+CB2−2r2

AP and TS EAMCET Engineering Model Paper 17

Question : 54 of 160

Marks: +1, -0

If C is the centre, r is radius of the circle S≡x2+y2+2gx +2fy+c=0 and A(x1,y1),B(x2,y2) are conjugate points with respect to S = 0 then AB2=

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