If C is the centre , r is radius of the circle S \equivx^2+y^2+2gx+2fy+c=0 and A(x_1,y_1),B(x_2,y_2) are conjugate points with respect to S=0 then \AB^2=

Correct Answer is : CA2+CB2−2r2

AP and TS EAMCET Engineering Model Paper 15

Question : 65 of 160

Marks: +1, -0

If C is the centre , r is radius of the circle S≡x2+y2+2gx+2fy+c=0 and A(x1,y1),B(x2,y2) are conjugate points with respect to S=0 then AB2=

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