The locus of the feet of the perpendiculars from centre of the ellipse { x ^ { 2 } } /{ a ^ { 2 } } + { y ^ { 2 } }/ { b ^ { 2 } } = 1 to any tangent is:

Correct Answer is : a2x2+b2y2=(x2+y2)2

a ^ { 2 } x ^ { 2 } + b ^ { 2 } y ^ { 2 } = ( x ^ { 2 } + y ^ { 2 } ) ^ { 2 }

a ^ { 2 } x ^ { 2 } + b ^ { 2 } y ^ { 2 } = x ^ { 2 } + y ^ { 2 }

a ^ { 2 } x ^ { 2 } + b ^ { 2 } y ^ { 2 } = x ^ { 2 } - y ^ { 2 }

a ^ { 2 } x ^ { 2 } + b ^ { 2 } y ^ { 2 } = ( x ^ { 2 } - y ^ { 2 } ) ^ { 2 }

AP and TS EAMCET Engineering Model Paper 13

Question : 62 of 160

Marks: +1, -0

The locus of the feet of the perpendiculars from centre of the ellipse

=1 to any tangent is:

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