\ov { \\alpha } = x ( \ov { a }\times \ov { b } ) + y ( \ov { b }\times \ov { c } ) + z ( \ov { c } \times \ov { a } ) and [ { \ov { a } } { \ov { b } } { \ov { c } } ] = { 1 }/ { 8 } then x + y + z = ?

Correct Answer is : 8α.(a+b+c)

8\ov { \\alpha} . ( \ov { a } + \ov { b } + \ov { c } )

\ov { \\alpha} . ( \ov { a } + \ov { b } + \ov { c } )

8. ( \ov { a } + \ov { b } + \ov { c } )

\ov { a } + \ov { b } + \ov { c }

AP and TS EAMCET Engineering Model Paper 13

Question : 21 of 160

Marks: +1, -0

α=x(a×b)+y(b×c)+z(c×a)

and [a‌b‌c]=

then x+y+z= ?

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