The perpendicular distance of any point \ov { a } on to the line \ov { r } = \ov { b } + t\ov { c } is

Correct Answer is : |(a−b)×c||−c|

{ | ( \ov { a } - \ov { b } ) \times \ov { c } | } /{ | { b^{ -}} | }

{ | ( \ov { a } - \ov { b } ) \times \ov { c } | } /{ | { c^{ -}} | }

{ | \ov { a } - \ov { b } | } /{ | { c^{ -}} | }

{ | ( \ov { a } - \ov { b } ) \times \ov { c } | } /{ | { a^{ -}} | }

AP and TS EAMCET Engineering Model Paper 11

Question : 21 of 160

Marks: +1, -0

The perpendicular distance of any point a on to the line r=b+tc is

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