The end product (Z) in the given sequence of reaction given below is { CH } _ { 3 } { CH } = { CHCHO }\stackrel{ N a B H _ { 4 }{----\to} } X\stackrel{HCl}{----\to}_{ZnCl_2}Y \stackrel{( i ) K C N}{----\to}_{( i i ) H ^ { + }}Z

Correct Answer is : CH3CH=CHCH2COOH

C H _ { 3 } C H = C H C H _ { 2 } C O O H

{ CH } _ { 3 } { CH } _ { 2 } { CH } _ { 2 } { COOH }

{ CH } _ { 3 } { CH } ( { Cl } ) { CH } _ { 2 } { COOH }

AP and TS EAMCET Engineering Model Paper 11

Question : 160 of 160

Marks: +1, -0

The end product (Z) in the given sequence of reaction given below is

CH3CH=CHCHO

NaBH4

−−−−→

HCl

−−−−→

ZnCl2

(i)KCN

−−−−→

(ii)H+

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