The perpendicular distance of any point \ov { a } to the line \ov { r } = \ov { b } + t \ov { c }

Correct Answer is : |(a−b)×c||−c|

{ ( \ov { a } - \ov { b } ) \times\ov { c } }/ { c^{-} }

{ |( \ov { a } - \ov { b } ) \times\ov { c } |}/ {| c ^{-}|}

{ | \ov { a } - \ov { b } | } /{ | { c^{-} } | }

{ | ( \ov { a } - \ov { b } ) \times \ov { c } | }/ { | { a^{-} } | }

AP and TS EAMCET Engineering Model Paper 10

Question : 18 of 160

Marks: +1, -0

The perpendicular distance of any point a to the line r=b+tc

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