H _ { 3 } C - C \equiv C H\stackrel{Na}{–––▶}A\stackrel{CH_3Cl}{–––––▶}B, then‘B’ is

Correct Answer is : H3C−C≡C−CH3

H _ { 3 } C - C \equiv C - C H _ { 3 }

C H _ { 3 } - H C = C H - C H _ { 3 }

C H _ { 3 } - C H _ { 2 } - C H _ { 2 } - C H _ { 3 }

C H _ { 2 } = C H - C H _ { 2 } - C H _ { 3 }

AP and TS EAMCET Engineering Model Paper 10

Question : 137 of 160

Marks: +1, -0

H3C−C≡CH

–––▶

CH3Cl

–––––▶

B, then‘B’ is

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